9v^2+18v=7

Solution for 9v^2+18v=7 equation:

9v^2+18v=7

We move all terms to the left:

9v^2+18v-(7)=0

a = 9; b = 18; c = -7;
Δ = b2-4ac
Δ = 182-4·9·(-7)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-24}{2*9}=\frac{-42}{18}
=-2+1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+24}{2*9}=\frac{6}{18}
=1/3
$